Calculate the impulse of a 0.140 kg baseball that starts at rest on a tee and reaches a final velocity of 20 m/s after being struck with a force of 100 N.

Question

Physics

Lane Irwin

15 December, 14:19

Calculate the impulse of a 0.140 kg baseball that starts at rest on a tee and reaches a final velocity of 20 m/s after being struck with a force of 100 N.

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Answers (2)

Know the Answer?

Bridger Mueller · Answer 1

impulse = change in momentumF*t = m (v-u) I = 0.140 (20-0) I = 0.140 * 20I = 2.8NS

Ashley Jennings · Answer 2

Answer: 2.8 Ns

Explanation:

Given that,

impulse I = ?

Mass of baseball M = 0.140 kg

Initial velocity (at rest) Vi = 0m/s

final velocity Vf = 20 m/s

force F = 100 N

Recall that impulse is the product of force and the time during which it acts

i. e Impulse = Force x Time

(since impulse is also equal to change in momentum, then

impulse = Ft = M x (Vf - Vi)

So, apply I = M x (Vf - Vi)

I = 0.140kg x (20 m/s - 0 m/s)

I = 0.140kg x (20 m/s)

I = 2.8 Ns

Thus, the impulse of the baseball is 2.8 Ns