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11 January, 04:37

A man walks backward on a bus. To a stationary observer, the bus moves

east at a speed of 15 m/s. If the man moves 2.3 m/s west relative to the bus,

what is his velocity in the frame of reference of a stationary observer?

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Answers (1)
  1. 11 January, 07:29
    0
    V (m, b) = V (m, e) - V (b, e)

    2.3m/s (west) = V (m, e) - 15m/s (east)

    to solve this change the direction of slower speed. so it will become negative value

    -2.3m/s (east) = V (m, e) - 15m/s (east)

    V (m, e) = 15m/s (east) - 2.3m/s (east)

    V (m, e) = 12.7 m/s (east)

    velocity of the man in frame of reference of stationary observer is 12.7 m/s

    it's slightly less than the velocity of bus so stationary observer see the man move slower than the one inside the bus

    ps: - V (m, b) - velocity of man relative to bus

    V (b, e) - velocity of bus relative to earth

    V (m, e) - velocity of man relative to earth
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