Ask Question
1 June, 22:03

A square loop of wire is held in a uniform 0.24 T magnetic field directed perpendicular to the plane of the loop. The length of each side of the square is decreasing at a constant rate of 5.4 cm/s. What emf is induced in the loop when the length is 14 cm?

+2
Answers (1)
  1. 2 June, 00:29
    0
    Given that,

    Magnetic field of 0.24T

    B = 0.24T

    Field perpendicular to plane i. e 90°

    Rate of decrease of length of side of square is 5.4cm/s

    dL/dt = 5.4cm/s = 0.054m/s

    Since it is decreasing

    Then, dL/dt = - 0.054m/s

    When L is 14cm, what is the EMF induced?

    L = 14cm = 0.14m

    EMF is give as

    ε = - dΦ/dt

    Where flux is given as

    Φ = BA

    Where A is the area of the square

    A = L²

    Then, Φ = BL²

    Substituting this into the EMF

    ε = - dΦ/dt

    ε = - d (BL²) / dt

    B is constant

    ε = - Bd (L²) / dt

    ε = - 2BL dL/dr

    ε = - 2 * 0.24 * 0.14 * - 0.054

    ε = 3.63 * 10^-3 V

    ε = 3.63mV
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A square loop of wire is held in a uniform 0.24 T magnetic field directed perpendicular to the plane of the loop. The length of each side ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers