Billiard ball A, mass 0.17 kg, moving due east with a velocity of 4.0 m/s, strikes stationary billiard ball B, also mass of 0.17 kg. After the collision, ball A moves off at an angle of 30° north of east with a velocity of 3.5 m/s, and ball B moves off at an angle of 60 ° south of east. What is the speed of ball B?

Question

Physics

Esperanza Bailey

23 January, 15:06

Billiard ball A, mass 0.17 kg, moving due east with a velocity of 4.0 m/s, strikes stationary billiard ball B, also mass of 0.17 kg. After the collision, ball A moves off at an angle of 30° north of east with a velocity of 3.5 m/s, and ball B moves off at an angle of 60 ° south of east. What is the speed of ball B?

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Answers (1)

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Camryn Adams · Answer 1

speed of ball B is 0.5 m/s

Explanation:

First the angle at which it's invliy does not matter.

Initial momentum is equall to final momentum.

M1v1 + m2v1 = m1v2 + m2v2

0.17*4 + (0.17*0) = 0.17*3.5 + 0.17v2

0.68 + 0 = 0.595 + 0.17v2

0.68-0.595 = 0.17v2

0.085 = 0.17v2

0.5 = v2

V2 = 0.5 m/s