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19 June, 17:53

A ball hits a wall horizontally at 6m/s and rebounces at 4.4m/s the ball is in contact with wall for 0.04 sec. what is the acceleration.

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  1. 19 June, 19:25
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    Acceleration (a) = 40 m/s²

    Explanation:

    Given:

    Initial velocity (u) = 6 m/s

    Final velocity (v) = 4.4 m/s

    Time taken (t) = 0.04sec

    Find:

    Acceleration (a) = ?

    Computation:

    We know that,

    ⇒ v = u + at

    ⇒ a = (v - u) / t

    ⇒ Acceleration (a) = (4.4 - 6) / 0.04

    ⇒ Acceleration (a) = (-1.6) / 0.04

    Acceleration (a) = 40 m/s²
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