an oil drop of mass 2*10^14 kg carries a charge of 8*10^-18C. The drop is stationary between two parallel plates 20mm apart with a potential difference of V between them. Calculate V

Given dа ta:

mass of oil = 2 * 10¹⁴ kg,

charge (q) = 8 * 10⁻¹⁸ C

drop is stationery between two parallel plates

and plates are at a distance of (d) = 20 mm

= 0.020 m,

Calculate potential difference (V) = ?

We know that the potential difference

V = E. d Volts

Where

d = distance between plates in meters

E = electric field in N/C

= m. g/q

q = charge in coulombs

m = mass in kg

Lets find out

E = m. g/q N/C

= (2 * 10¹⁴ * 9.8) / 8*10⁻¹⁸ N/C

= 2.45 * 10³² N/C

Now calculating V = E. d

= 2.45 * 10³² * 0.020

= 4.9 * 10³⁰ volts

The potential difference is 4.9 * 10³⁰ volts