Water has the highest heat of vaporization of any liquid, which makes it very important in the temperature regulation of the human body. If 8.5 grams of water, in the form of sweat for example, evaporates from your skin, how much heat will be released from the body?

1918.62 kj

Explanation:

The heat of vaporization of water is 540cal/g.

Temperature of vaporization of water is 100°c.

Mass of water is 8.5grams.

Heat released = mc (tita)

Heat released = 8.5*540*100

Heat released = 459000 cal

1 kilocalorie =

4.184 kilojoules

459000 cal = 459 kc

459 kc = 459*4.18

459 kc = 1918.62 kj

Heat Loss of, q = 19.21 KJ

Explanation:

Given:-

- The mass of water, m = 8.5 g

- The latent heat of vaporization of water, Lv = 2,260 kJ/kg.

Find:-

how much heat will be released from the body when the sweat evaporates?

Solution:-

- The heat loss of water assuming conditons of evaporation only depedns on the amount (mass) of water and its latent heat of vaporisation i. e (its phase change from liquid to gaseous form). We can write the heat loss (q) as following:

q = m*Lv

- Plug in the given values:

q = (8.5 / 1000) * (2,260)

q = 19.21 KJ