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11 January, 05:37

A wire with a weight per unit length of 0.075 N/m is suspended directly above a second wire. The top wire carries a current of 29.2 A and the bottom wire carries a current of 59.1 A. Find the distance of separation between the wires so that the top wire will be held in place by magnetic repulsion.

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  1. 11 January, 07:06
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    force between two current carrying conductor per unit length

    = (μ₀ / 4π) x (2 i₁i₂ / R), i₁ and i₂ be current in them, R is distance between two,

    = 10⁻⁷ x 2 x 29.2 x 59.1 / R.

    This force balances weight of wire per unit length

    = 10⁻⁷ x 2 x 29.2 x 59.1 / R. =.075

    = 10⁻⁷ x 2 x 29.2 x 59.1 /.075 = R

    R = 4.6 x 10⁻³ m

    4.6 mm.
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