Ask Question
18 February, 17:53

A baseball pitcher brings his arm forward during a pitch, rotating the forearm about the elbow. If the velocity of the ball in the pitcher's hand is 34.9 m/s (about 78 mph) and the ball is 0.310 m from the elbow joint, what is the angular velocity of the forearm

+1
Answers (1)
  1. 18 February, 20:02
    0
    112.581 rad/s.

    Explanation:

    Angular velocity: This can be defined as the velocity of a body undergoing angular motion. The S. I unit of angular velocity is rad/s.

    From the question, The expression for angular velocity is given as,

    ω = v/r ... Equation 1

    Where ω = angular velocity of the forearm, v = velocity of the ball in the pitcher's hand, r = the distance of the ball from the elbow joint.

    Given: v = 34.9 m/s, r = 0.310 m

    Substitute into equation 1

    ω = 34.9/0.310

    ω = 112.581 rad/s.

    Hence the angular velocity of the forearm = 112.581 rad/s.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A baseball pitcher brings his arm forward during a pitch, rotating the forearm about the elbow. If the velocity of the ball in the ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers