The speed of an object undergoing constant acceleration increased from 8.0 meters per second to 16.0 meters per second in 10. Seconds. How far does the object travel during the 10. Seconds

v₀ = initial speed of the object = 8 meter/second

v = final speed of the object = 16 meter/second

t = time taken to increase the speed = 10 seconds

d = distance traveled by the object in the given time duration = ?

using the kinematics equation

d = (v + v₀) t/2

inserting the above values in the above equation

d = (16 + 8) (10) / 2

d = 120 meter