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22 November, 15:02

A stone is dropped from a tower of height 3600cm. Find the velocity by which it strike the ground. Find the time taken to reach the ground.

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  1. 22 November, 17:25
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    1. 26.56m/s.

    2. 2.71 secs.

    Explanation:

    The following data were obtained from the question:

    Height (h) = 3600cm

    Velocity (v) = ... ?

    Time (t) = ... ?

    Next, we shall convert the height, 36000cm to metre (m). This is illustrated below:

    100cm = 1m

    Therefore, 3600cm = 3600/100 = 36 m

    Therefore, the height is 36m.

    1. Determination of the velocity with which the stone struck the ground. This is illustrated below:

    Acceleration due to gravity (g) = 9.8m/s²

    Height (h) = 36m

    Velocity (v) =.?

    v² = 2gh

    v² = 2 x 9.8 x 36

    v² = 705.6

    Take the square root of both side.

    v = √705.6

    v = 26.56m/s

    Therefore, the velocity with which the stone struck the ground is 26.56m/s.

    2. Determination of the time taken for the stone to reach the ground.

    Height (h) = 36m

    Acceleration due to gravity (g) = 9.8m/s²

    Time (t) =.?

    t = √ (2h/g)

    t = √ (2 x 36 / 9.8)

    t = √ (72/9.8)

    t = 2.71 secs

    Therefore, the time taken for the stone to reach the ground is 2.71 secs
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