The following equation is an example of decay?

232/90 TH---4/2 HE + 228/88 RA?

Alpha decay

Explanation:

Alpha decay is one of the three major types of decays, others being, beta decay and gamma decay. When a radioactive isotope undergoes alpha decay it emits alpha particles. An alpha particle is equivalent to the nucleus of Helium atom. Therefore, an atom undergoing decay, its atomic mass is decreased by 4 and its atomic number is decreased by 2. Thus, since 232/90 Th, has undergone alpha decay its mass number is reduced by 4 to 228 and its atomic number by 2 to 88, and becomes 228/88 Ra.