What is the internal energy of 3.00 mol of N2 gas at 25 degrees C? To solve this problem, use the equation: U electronic gas = 5/2nRT. Remember that R = 8.31 J / (mol-K) and K = degrees + 273.

A. 37, 100 J

B. 18,600 J

C. 1560 J

D. 623 J

Given data

Determine Internal energy of gas N₂, (U) = ?

Temperature (T) = 25° C

= 25+273 = 298 K,

Gas constant (R) = 8.31 J / mol-K,

Number of moles (n) = 3 moles,

Internal energy of N₂

Internal energy is a property of thermodynamics, the concept of internal energy can be understand by ideal gas. For example N₂, the observations for oxygen and nitrogen at atmospheric temperatures, f=5, (where f is translational degrees of freedom).

So per kilogram of gas,

The internal energy (U) = 5/2. n. R. T

= (5/2) * 3 * 8.31 * 298

= 18572.85 J

The internal energy of the N₂ is 18,572.85 J and it is approximately equal to 18,600 J given in the option B.