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6 March, 14:46

A 30 nc charge experiences a 0.047 n electric force. what is the magnitude of electric field at the position of this charge?

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  1. 6 March, 15:35
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    Electric force = electric field * charge

    F = E*C = > E = F / C = 0.047 N / 30 nC = 0.00157 N/nC = 0.00157 * 10^9 N/C = 1.57 * 10^6 N/C
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