Ask Question
28 April, 17:08

Calculate the power in kilowatts required to lift a 500 kg mass 12 meters in one second

+5
Answers (1)
  1. 28 April, 18:01
    0
    The weight of the load is (mass) x (gravity).

    The work done to lift it is (weight) x (distance) = (mass) x (gravity) x (distance)

    The power is (work) / (time) =

    (mass) x (gravity) x (distance) / (time) =

    (500 kg) x (9.8 m/s²) x (12 m) / (1 sec) =

    (500 x 9.8 x 12 / 1) (kg-m / sec²) (m) / (sec) =

    (500 x 9.8 x 12 / 1) newton - meter / sec =

    (500 x 9.8 x 12 / 1) joule / sec =

    58,800 watts

    = 58.8 kW

    = about 78.8 horsepower
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Calculate the power in kilowatts required to lift a 500 kg mass 12 meters in one second ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers