0.100kg of a nuclear is converted to energy per day. What is the power produced by this fuel?

This problem is just what everybody likes to see:

A direct application of E=mc²!

If 0.100m kg of matter is converted to energy,

the quantity of energy is

E = m c²

= (0.1 kg) · (3 x 10⁸ m/s) ²

= (0.1 kg) · (9 x 10¹⁶ m²/s²)

= (9 x 10¹⁵) (kg-m/s²) (m)

= (9 x 10¹⁵) (Newton) (m)

= (9 x 10¹⁵) Joules.

Thatsa lotta energy, Bub!

1 day = 86,400 seconds

Power = (energy) / (time)

= (9 x 10¹⁵ joules) / (86,400 seconds)

= 1.041 x 10¹¹ joules/sec

= almost exactly 1 gigawatt.