A 0.63kg mass rests on top of a vertical spring with spring constant 65N/m. When the mass sits at rest, determine the distance that the spring is compressed from it's equilibrium position.

Question

Physics

Kinsley Olsen

2 November, 08:48

A 0.63kg mass rests on top of a vertical spring with spring constant 65N/m. When the mass sits at rest, determine the distance that the spring is compressed from it's equilibrium position.

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Brenden Kent · Answer 1

The mass will sag lower and lower and compress the spring, until the

upward force of the spring is equal to the weight of the mass. When

that happens, the two forces on the mass (gravity and spring) will be

balanced, and the mass will stop sinking.

- - The weight of the mass is (mass) x (gravity) = (0.63) x (9.8) Newtons.

- - The distance that the spring is compressed is 1 meter / 65 newtons.

(1 meter/65 newtons) x (0.63 x 9.8) newtons = 0.095 meter = 9.5 centimeters