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2 December, 16:07

If a system has 475 kcal of work done to it, and releases 5.00 * 102 kJ of heat into its surroundings, what is the change in internal energy of the system?

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  1. 2 December, 16:23
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    First, we convert kcal to joules:

    1 kcal = 4.184 kJ

    475 kcal = 1987.4 kJ

    Now, calculating the change in internal energy:

    ΔU = Q + W; where Q is the heat supplied to the system and W is the work done on the system.

    ΔU = - 500 + 1987.4

    ΔU = 1487.4 kJ
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