A tornado lifts a truck 252 m above the ground. As the storm continues, the tornado throws the truck horizontally. It lands 560 m away from where it was picked up.

How fast was the truck traveling horizontally through its flight? Round your answer to the nearest tenth.

Treat that like a projectile the gravity is with the truck accelerating it. initial velocity = 0, initial height = 252

dy = vo + 0.5gt^2

252 = 0 + 5t^2

t = 7.099 s

in horizontal direction no gravity so, it's just motion in straight line

v = displacement/t = 560/7.099 = 78.88 m/s