Calculate the number of Joules given off by 617 grams of water cooling from 65°C to 28°C. [Cw=4.186 J/g*Co]

Q=mC_w/Delta T

The heat energy lost or gained by a substance is given by the equation

Q = mCΔT, where

Q is the heat energy gained or lost by a substance,

m is mass (in grams),

C is the specific heat of the substance,

ΔT is the change in temperature (final temperature - initial temperature).

The joules given off by 617 grams of water cooling from 65°C to 28°C, given the specific heat of water as Cw=4.186 J/g*Co, is:

Q = mCwΔT

Q = (617) (4.186) (28 - 65)

Q = - 95562.194

Negative means heat is lost, so 96000 J of heat was lost.