The froghopper (philaenus spumarius, the champion leaper of the insect world, has a mass of 12.3mg and leaves the ground (in the most energetic jumps at 4.00m/s from a vertical start. the jump itself lasts a mere 1.00ms before the insect is clear of the ground. (a find the force that the ground exerts on the froghopper during its jump. (b express the force of (a in terms of the frog hoppers weight.

Question

Physics

Leland Friedman

17 March, 19:17

The froghopper (philaenus spumarius, the champion leaper of the insect world, has a mass of 12.3mg and leaves the ground (in the most energetic jumps at 4.00m/s from a vertical start. the jump itself lasts a mere 1.00ms before the insect is clear of the ground. (a find the force that the ground exerts on the froghopper during its jump. (b express the force of (a in terms of the frog hoppers weight.

+5

Answers (1)

Know the Answer?

Jayden Thompson · Answer 1

First, the acceleration is solved by dividing the velocity by time.

acceleration = 4 m/s / (1x10^-3s) = 4000 m/s²

Then, we solve for the force by multiplying the mass by acceleration.

F = m x a

Substituting the known values,

F = (12.3 mg) (4000 m/s²) = (12.3 x 10^-6 kg) (4000 m/s²)

F = 0.0492 N

Thus, the force of the froghopper is approximately equal to 0.0492 N.