Starting at a certain speed, a bicyclist travels 200m. Suppose the bicyclist undergoes a constant acceleration of 1.20m/s squared. If the final speed is 25.0m/s, what was the bicyclists initial speed?

Question

Physics

Diaz

20 November, 18:38

Starting at a certain speed, a bicyclist travels 200m. Suppose the bicyclist undergoes a constant acceleration of 1.20m/s squared. If the final speed is 25.0m/s, what was the bicyclists initial speed?

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Answers (1)

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Haynes · Answer 1

V2^2 = V1^2 + 2*a * s

V2 = final velocity

V1 = initial velocity

a = acceleration

s = displacement covered

25^2 = V1^2 + 2 * 1.2 * 200

625 = V1^2 + 480

625 - 480 = V1^2

145 = V1^2

So V1 = Sqrt (145) = 12.04 m/s