How much energy is needed to heat 3 kg of water through the following changes?

1. Heat 3 kg ice from - 10 C to 0 C

2. Melt 3 kg ice at 0 C

3. Heat 3 kg water from 0 C to 100 C

4. Vaporize 3 kg water at 100 C

5. Heat 3 kg steam from 100 C to 110

1. Heat 3 kg ice from - 10 C to 0 C

is sensible heating so

Q = m cp (T2 - T1)

Q = 3 kg (2.09 kJ/kg C) (0 - (-10)) C

Q = 62.7 kJ

2. Melt 3 kg ice at 0 C

requires latent heat so,

Q = m Hfus

Q = 3 kg (333.55 kJ/kg)

Q = 1000.65 kJ

3. Heat 3 kg water from 0 C to 100 C

requires

Q = 3 kg (4.18 kJ/kg C) (100 - 0) C

Q = 1254 kJ

4. Vaporize 3 kg water at 100 C

requires latent heat, so

Q = m Hvap

Q = 3 kg (2258.33 kJ/kg)

Q = 6775 kJ

5. Heat 3 kg steam from 100 C to 110

requires

Q = 3 kg (2.02 kJ/kg C) (110 - 100) C

Q = 60.6 kJ

Hello there.

How much energy is needed to heat 3 kg of water through the following changes?

1. Heat 3 kg ice from - 10 C to 0 C

62.7 kJ