A child pushes her toy across a level floor at a steady velocity of 0.50 m/s using an applied force of 2.0 N. If the weight of the toy is 8.0 N, what is the coefficient of sliding friction between the toy and the floor?

a. 0.25

b. 1.0

c. 4.0

d. 0.40

Since toy is moving at constant speed that means that force that child is applying on toy is equal to force of friction.

Rate of speed that toy is moving is irelevant.

childs force is:

Fc = 2N

Fc = Ff (Ff - friction force)

Ff = a*Q

where Q is weight of the toy and a is friction

if we express a we get

a = F/Q = 2/8 = 0.25