Ask Question
4 March, 09:37

A spring has a spring constant of 30000 N/m. How far must it be stretched (in meters) for its potential energy to be 47 J?

+1
Answers (1)
  1. 4 March, 13:16
    0
    The elastic potential energy in a spring is given by:

    EPE = 1/2 kx²

    x = √ (2 x 47 / 30,000)

    x = 0.056 m
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A spring has a spring constant of 30000 N/m. How far must it be stretched (in meters) for its potential energy to be 47 J? ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers