How much work did the movers do (horizontally) pushing a 160-kg crate 10.3 m across a rough floor without acceleration, if the effective coefficient of friction was 0.50?

Question

Physics

Peyton Gallagher

5 August, 04:44

How much work did the movers do (horizontally) pushing a 160-kg crate 10.3 m across a rough floor without acceleration, if the effective coefficient of friction was 0.50?

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Selina Clayton · Answer 1

We are given with a 160 kg crate in which it is moved by 10.3 meters and the coefficient of friction of the floor is equal to 0.50. The formula is expressed as W = F u d. substituting, W = 160 kg * 9.8 m/s2 * 0.5 * 10.3 m equal to 8075.2 joules.