A metal ball of mass 100 g is heated to 90°C and then cooled to 25°C. The heat lost in the process is 2.5 kJ. Another metal ball of mass 200 g is heated to 90°C and then cooled to 25°C. The heat lost in the process is 5.0 kJ. What can be concluded from the data?

Question

Physics

Naomi Yoder

26 March, 07:52

A metal ball of mass 100 g is heated to 90°C and then cooled to 25°C. The heat lost in the process is 2.5 kJ. Another metal ball of mass 200 g is heated to 90°C and then cooled to 25°C. The heat lost in the process is 5.0 kJ. What can be concluded from the data?

+2

Answers (1)

Know the Answer?

Karlee Nixon · Answer 1

Hey this is what i found on the internet

specific heat (Cp) - the heat required to raise the temperature of the unit mass of a given substance by a given amount (usually one degree)

the equation related to this theory is

Q=m Cp ΔT

Where Q is the energy gained or lost from the system

m is the mass of the object

Cp is the specific heat of the material

ΔT is the change in temperature