A circuit contains a 12 volt battery and two 3 ohm bulbs in series. Calculate the current

If there are two bulbs in series, and each bulb has

resistance = 3 ohms,

then their total resistance in series is 6 ohms.

When the series pair of bulbs is connected across the terminals

of the battery, the current through the circuit is

Current = (voltage) / (resistance)

= (12 volts) / (6 ohms) = 2 amperes