The Hubble telescope's orbit is 5.6 * 105 meters above Earth's surface. The telescope has a mass of 1.1 * 104 kilograms. Earth exerts a gravitational force of 9.1 * 104 newtons on the telescope. The magnitude of Earth's gravitational field strength at this location is

Question

Physics

Aleah

27 January, 07:59

The Hubble telescope's orbit is 5.6 * 105 meters above Earth's surface. The telescope has a mass of 1.1 * 104 kilograms. Earth exerts a gravitational force of 9.1 * 104 newtons on the telescope. The magnitude of Earth's gravitational field strength at this location is

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Bryant Wilkins · Answer 1

Gravitational force = 9.1 x 10⁴ newtons

Mass = 1.1 x 10⁴ kilograms

Gravitational field strength = 9.1 x 10⁴ newtons / 1.1 x 10⁴ kilograms

= (9.1 / 1.1) (newton / kilogram)

= 8.3 newton/kg

or 8.3 m/s².