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25 June, 06:53

In a ballistic pendulum experiment, projectile 1 results in a maximum height h of the pendulum equal to 2.0 cm. A second projectile causes the the pendulum to swing higher, to h2 = 5.5 cm. The second projectile was how many times faster than the first?

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  1. 25 June, 09:14
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    Assuming you mean " how fast at the bootom of the swing", since the speed of a pendulum is constantly changing. The key with pendulums is the transfer of energy from potential to kinetic. You can use the next formulas

    m1 ∗g∗ (2.0cm) = 12 m1 v2

    The speed of the bottom is equal to

    v = (√ 2∗g∗2.0cm)

    If a second pendulum reaches twice as high, substitute twice the height into the same equation
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