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13 August, 09:03

At about 55 meters per second, a falling parachuter (before the parachute opens) no longer accelerates. Air friction of 55 m/s. How long would that take?

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  1. 13 August, 12:29
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    Final velocity (vf) = 55 m/s, initial velocity = 0 m/s

    Assume that it is falling under free fall with g = 9.8 m/s²

    acceleration = Δvelovity/time

    time interval = (vf-vi) / t=g = 55/9.8 = 5.612 seconds
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