At about 55 meters per second, a falling parachuter (before the parachute opens) no longer accelerates. Air friction of 55 m/s. How long would that take?

Question

Physics

Kathy Bradshaw

13 August, 09:03

At about 55 meters per second, a falling parachuter (before the parachute opens) no longer accelerates. Air friction of 55 m/s. How long would that take?

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Answers (1)

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Braedon Carey · Answer 1

Final velocity (vf) = 55 m/s, initial velocity = 0 m/s

Assume that it is falling under free fall with g = 9.8 m/s²

acceleration = Δvelovity/time

time interval = (vf-vi) / t=g = 55/9.8 = 5.612 seconds