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7 December, 10:05

A box weighing 46 newtons rests on an incline that makes an angle of 25° with the horizontal. What is the magnitude of the component of the box's weight perpendicular to the incline?

(1) 19 N

(2) 21 N

(3) 42 N

(4) 46 N

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Answers (1)
  1. 7 December, 12:34
    0
    The magnitude of the component of the box’s weight perpendicular to the incline can be olve using the formula:

    F = wcos (a)

    Where F is the box’s weight perpendicular to the incline

    W is the weight of the box

    A is the angle of the incline

    F = (46) cos (25)

    F = 42 N
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