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26 February, 22:42

A particle with a charge of 3.00 elementary charges moves through a potential difference of 4.50 volts. What is the change in electrical potential energy of the particle?

(1) 1.07 * 10 19eV

(2) 2.16 * 10 18eV

(3) 1.50 eV

(4) 13.5 eV

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Answers (1)
  1. 27 February, 01:10
    0
    The answer:

    the relationship between elementary charge, potential difference and electrical potential energy is given by

    E = qV

    E: lectrical potential energy

    q: elementary charge

    V: potential difference

    but we have e=abs val (q) = 3

    so we have E = qV=3ex4.5V = 13.5 eV

    the answer is (4) 13.5 eV
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