A light beam is incident on a piece of fluorite (n = 1.434) at the Brewster's angle.

(a) Find the value of Brewster's angle.

°

(b) Find the angle of refraction for the transmitted ray.

The Brewster angle is the angle can be found through this equation

θ=arctan (n2/n1).

This came from Snell's Law:

n1sinθ=n2sin (90-θ)

=n2cosθ

n2/n1=tanθ - - - θ=arctan (n2/n1) = arctan (1.434) = 55.11 degrees

Next, the angle of refraction can be found by using Snell's Law

n1sinθ=n2sinθ'

sin (55.11) = 1.434sinθ'

sinθ'=sin (55.11) / 1.434=0.572 - - - θ'=arcsin (0.572) = 34.89 degrees