A 0.012kg rubber bullet travels at a velocity of 150m/s, hits a stationary 8.5kg concrete block resting on a frictionless surface, and ricochets in the opposite direction worth a velocity of - 100m/s. how fast will the concrete block be moving?

Question

Physics

Adyson Brown

24 April, 05:54

A 0.012kg rubber bullet travels at a velocity of 150m/s, hits a stationary 8.5kg concrete block resting on a frictionless surface, and ricochets in the opposite direction worth a velocity of - 100m/s. how fast will the concrete block be moving?

+3

Answers (1)

Know the Answer?

Jayce Davis · Answer 1

This can be solve using momentum balance

Momentum = mv

Where m is the mass of the object

V is the velocity of the object

(0.012 kg) (150 m/s) + (8.5 kg) (0 m/s) = (0.012 kg) (-100 m/s) + (v) (8.5 kg)

V = 0.35 m/s