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24 April, 05:54

A 0.012kg rubber bullet travels at a velocity of 150m/s, hits a stationary 8.5kg concrete block resting on a frictionless surface, and ricochets in the opposite direction worth a velocity of - 100m/s. how fast will the concrete block be moving?

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  1. 24 April, 07:23
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    This can be solve using momentum balance

    Momentum = mv

    Where m is the mass of the object

    V is the velocity of the object

    (0.012 kg) (150 m/s) + (8.5 kg) (0 m/s) = (0.012 kg) (-100 m/s) + (v) (8.5 kg)

    V = 0.35 m/s
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