Ask Question
8 September, 14:12

The orbital period of an object is 2 * 107 s and its total radius is 4 * 1010 m.

+2
Answers (1)
  1. 8 September, 15:22
    0
    The orbital period of an object is 2 * 107 s and its total radius is 4 * 1010 m is equals to 1.256*10^4 m/sec. Below is the solution:

    V = C/t = 6.28*4*10^10 / (2*10^7) = 1.256*10^4 m/sec
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “The orbital period of an object is 2 * 107 s and its total radius is 4 * 1010 m. ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers