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16 August, 05:59

A shot-putter throws the shot with an initial speed of 15.5m/s at a 34 degree angle to the horizontal. calculate the horizontal distance traveled by the shot if it leaves the athlete's hand at a height of 2.20m above the ground.

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  1. 16 August, 09:37
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    This can be solve by using the formula

    x = (v^2) (sin 2a) / gwhere v is the intial velocitya is the angle of trajectoryg is the acceleration due to gravity (9.8 m/s2)

    x = (15.5^2) (sin 2 (34) / 9.8x = 22.73 m
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