A 75 kg box slides down a 25.0 degree ramp with an acceleration of 3.60 m/s^2.

Find coefficient between the box and the ramp. What acceleration would a 175 kg box have on this ramp?

Below is the solution:

angle = 25 deg

m = 75kg

a = 3.6m/s/s

F[x] = 75 (9.8) sin (25) = 310.62N

f[y] = 75 (9.8) cos (25) = 666.1N

f=ma

310.62 - 666.1u = 75 (3.6)

666.1u = 310.62 - 270 = 40.62

u = 0.061

175 (9.8) sin (25) - 175 (9.8) (0.061) cos (25) = 175a

175a = 724.79 - 95.587 = 629.203

a = 3.595 m/s/s