A motorcycle being driven on a dirt path hits a

rock. Its 60.-kilogram cyclist is projected over

the handlebars at 20. meters per second into a

haystack. If the cyclist is brought to rest in

0.50 second, the magnitude of the average force

exerted on the cyclist by the haystack is

(1) 6.0 * 10^1 N (3) 1.2 * 10^3 N

(2) 5.9 * 10^2 N (4) 2.4 * 10^3 N

Question

Physics

Pranav

23 February, 23:03

A motorcycle being driven on a dirt path hits a

rock. Its 60.-kilogram cyclist is projected over

the handlebars at 20. meters per second into a

haystack. If the cyclist is brought to rest in

0.50 second, the magnitude of the average force

exerted on the cyclist by the haystack is

(1) 6.0 * 10^1 N (3) 1.2 * 10^3 N

(2) 5.9 * 10^2 N (4) 2.4 * 10^3 N

+2

Answers (1)

Know the Answer?

Jair Zimmerman · Answer 1

Impulse = mass * change in velocity (change in momentum) = Force * change in time

So, F = (m*change in v) / (change in t)

F = (60*20) / 0.5=2400N

Therefore the magnitude of the average force exerted on the cyclist by the haystack is 2.4*10^3N