Ask Question
10 May, 07:28

Two oppositely charged parallel metal plates,

1.00 centimeter apart, exert a force with a

magnitude of 3.60 * 10^-15 newton on an electron

placed between the plates. Calculate the

magnitude of the electric field strength between

the plates. [Show all work, including the

equation and substitution with units.]

+4
Answers (1)
  1. 10 May, 10:14
    0
    Electric field strength = Force/Charge

    E = (3.6*10^-15) / (1.6*10^-19) = 2.25*10^4 N/c

    1.6*10^-19 being the elementary charge that is a fundamental constant, and is the charge on an electron.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Two oppositely charged parallel metal plates, 1.00 centimeter apart, exert a force with a magnitude of 3.60 * 10^-15 newton on an electron ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers