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6 May, 13:22

How much total energy is dissipated in 10. seconds

in a 4.0-ohm resistor with a current of

0.50 ampere?

(1) 2.5 J (3) 10. J

(2) 5.0 J (4) 20. J

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Answers (1)
  1. 6 May, 13:57
    0
    The equation to use here for power dissipated across a component is P = I^2R

    Substituting the values into the equation:

    P = 4^2 x 0.5 = 16x0.5=8W

    The unit for watts is joules per second, and we want energy dissipated over 10 seconds, so:

    8x10=80

    Therefore 80J of Energy is dissipated
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