An electron in a mercury atom changes from energy level b to a higher energy level when the

atom absorbs a single photon with an energy of 3.06 electronvolts.

Calculate the frequency of the photon. [Show all work, including the equation and substitution

with units.]

Question

Physics

Elliot Stark

29 September, 05:27

An electron in a mercury atom changes from energy level b to a higher energy level when the

atom absorbs a single photon with an energy of 3.06 electronvolts.

Calculate the frequency of the photon. [Show all work, including the equation and substitution

with units.]

+4

Answers (1)

Know the Answer?

Rodney Buck · Answer 1

E = hf, where E is the energy of the photon, h the planck's constant, and f the frequency of the photon. Hence f = E/h, f = 3.06 eV / (6.63 x 10^-34 m^2 kg/s),

f = (1.6 x 10^-19 kg m^2/s^2) / (6.63 x 10^-34 m^2 kg/s) = 2.41 x 10^14 Hz

An electron in a mercury atom changes from energy level b to a higher energy level when theatom absorbs a single photon with an energy of 3.06 electronvolts.Calculate the frequency of the photon. [Show all work, including the equation and substitutionwith units.]

An electron in a mercury atom changes from energy level b to a higher energy level when the

atom absorbs a single photon with an energy of 3.06 electronvolts.

Calculate the frequency of the photon. [Show all work, including the equation and substitution

with units.]