Two conducting parallel plates 5.0 * 10-3 meter apart are charged with a 12-volt potential

difference. An electron is located midway between the plates. The magnitude of the electrostatic

force on the electron is 3.8 * 10-16 newton.

Calculate the magnitude of the electric field strength between the plates, in newtons per coulomb

Question

Miley

11 June, 16:59

+2

Answers (1)

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Shayla Leonard · Answer 1

E = F/q where E is the electric field strength, F is the force and q is the charge. So E = (3.8 x 10^-16N) / (1.6 x 10^-19) C = 2375 N/C