Sylvanite is a mineral that contains 28.0% / % gold by mass. How much sylvanite would you need to dig up to obtain 34.0g g of gold?

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Physics

Ivan Owens

24 August, 00:57

Sylvanite is a mineral that contains 28.0% / % gold by mass. How much sylvanite would you need to dig up to obtain 34.0g g of gold?

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Keon · Answer 1

Since it is said the 1g of mineral contains 28% of gold which is equivalent to. 28g of gold. Thus,.28 gram of Gold = 100 grams of Minerals

=> 1g of Gold = 100/28 grams of Minerals

=> 34grams of gold = 100/28 * 34 g of Minerals

=> 34 grams of gold = 952 grams of Minerals

Therefore, it needs 952 grams of Sylvanite minerals in order to have 34 grams of Gold.