Calculate the earth's gravity force on a 65 kg astronaut who is repairing the hubble space telescope 600 km above the earth's surface

Let Fgrav=earth's gravity force (N) = asked,

m1=mass of astronaut (kg) = 65kg,

m2=mass of the earth (kg) = 5.98x10^24 kg,

G=universal gravitation constant=6.673x10^-11 Nm^2/kg^2

d1=distance from the surface of the earth to its center=6.38x10^6m

d2=distance of the astronaut from the surface of the earth=600km=6x10^5m

d=d1+d2, since the astronaut is above the surface of the earth

d=6.38x10^6m + 6x10^5m=6,980,000m

Working equation: Fgrav = (Gm1m2) / d^2

Fgrav = (6.673x10^-11 Nm^2/kg^2) (65kg) (5.98x10^24 kg) / (6,980,000m) ^2

Fgrav=532.38 N