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6 October, 06:12

What is the magnitude of the orbital velocity of the earth in m/s?

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  1. 6 October, 09:14
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    Circumference C=2πr

    C=2π (1.5x10^8) = 9.42x10^8

    In 365 Days there are 8760hr

    V=distance/time

    V = (9.42x10^8) / 8760=107534.2km/hr
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