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13 April, 18:29

A ball is thrown straight upward from ground level with a velocity of 18m/s How much time passes before the ball strikes the ground? Disregard air resistance.

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  1. 13 April, 19:50
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    The displacement of the ball can be calculated using:

    s = ut + 1/2 at²; where u is the initial velocity and a is the acceleration. Because these are in opposite directions, one will be given a negative sign.

    s = 0 at ground level

    s = 18t - 1/2 x 9.81t²

    t (18 - 4.9t) = 0

    t = 0; t = 3.67 seconds

    Thus, the ball will come back and strike the ground at 3.67 seconds.
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