While watching a small fireworks display from a building 204 feet tall, you observe a rocket that travels from ground to eye level in 6 seconds, and explodes. What is the maximum speed that you can guarantee that the rocket reached?

204 ft = 62.2 m

We know that the initial velocity of the rocket was 0, we can find its acceleration using:

s = ut + 1/2 at²

62.2 = 0.5a (6) ²

a = 3.46 m/s²

Now, the final velocity of the rocket:

v = u + at

v = 3.46 x 6

v = 20.76 m/s = 68.1 ft/s