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23 April, 14:13

What is the emf produced in a 1.5 meter wire moving at a speed of 6.2 meters/second perpendicular to a magnetic field of strength 3.96 * 10-3 newtons/amp·meter?

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  1. 23 April, 15:36
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    General formula for emf is: emf=vBL (sin θ) ... (1) As the angle here is 90° and sin90°=1. So, equation (1) becomes; emf=vBL Putting values; emf = (6.2) (1.5) (3.96 * 10^-3) = 0.0369 volts
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