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16 August, 16:45

How fast must a 6.0-kg cat run to have a kinetic energy of 150 J?

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  1. 16 August, 17:46
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    KE = 1/2 * mv^2

    150 J = 1/2 * 6 kg * v^2

    v^2 = (150 J) / (6 kg) (1/2)

    = 50 m/s

    V = sqrt (50 m/s)

    5*sqrt (2)

    ~ 7.07 m/s
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